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110V Electrical Outlet Specs

TxTruckMan
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TxTruckMan Senior Enthusiast

TxTruckMan

Posted
Posted

Does anybody know how many amps the 110V electrical outlets can handle? I'm wondering if I can run a Coleman air bed pump from one of these? Is it about the same as the 12V plug or more/less? I want to buy an air pump for camping, but I also want to be able to use it around the house, so 110V version is preferable it the truck can run it.

 

Thanks.

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Newell33
Newell33
roadblock
roadblock

You will be fine, I have done this many times with no issue.  

sahls01gmc
sahls01gmc

^^^^^^^^^ 150 watts = 120volts x 1.25amps.   The inverter only puts out 150 watts.

newdude Senior Enthusiast

newdude

Posted
Posted

The alternating current (AC) accessory power outlet system consists of the accessory DC/AC power inverter module and the accessory power receptacle – 110 V AC. The accessory DC/AC power inverter module converts 12 V direct current (DC) battery power to 110 V at 60 Hertz (Hz) AC power to operate AC powered devices. The accessory DC/AC power inverter module provides up to 150 watts of power. The accessory power receptacle – 110 V AC provides the usual connection for AC powered devices.

 

TenofMe Enthusiast

TenofMe

Posted
Posted

The AC outlet is a joke. I plugged my Makita charger into it, and it tripped immediately. Why even put on in there in the first place?

 

You can plug the pump in and see if it trips.

Texas Sticks Enthusiast

Texas Sticks

Posted
Posted

Okay. Here's the equation:

 

P=VI (Power (watts) = Voltage (volts) x Current (amps))

 

With the numbers provided above, the available current (I, in amps)

should be...

 

I = 150/12 = 12.5 A

 

Yes, I am a physics nerd.

00Silverado4x4 Senior Enthusiast

00Silverado4x4

Posted
Posted

Don't know the specs but can tell you I tried using my 400w invertor to plug in a pump for an air mattress and it cut out immediately. I doubt the factory 110v plug will allow you to run that pump.

TxTruckMan Senior Enthusiast

TxTruckMan

Posted
  • Author
Posted

So, it looks like the 120V pump runs at ~250 watts after the initial ~450 watt surge. That won't cut it. I guess I'm going with the 12V pump.

Texas Sticks Enthusiast

Texas Sticks

Posted
Posted

12.5 amps should be plenty for most household appliances, even a microwave or a small refrigerator. I'd imagine, though, that you want to pull this much amperage only with the alternator turning/engine running.

Newell33 Enthusiast

Newell33

Posted
Posted

Okay. Here's the equation:

 

P=VI (Power (watts) = Voltage (volts) x Current (amps))

 

With the numbers provided above, the available current (I, in amps)

should be...

 

I = 150/12 = 12.5 A

 

Yes, I am a physics nerd.

 

Maybe I'm wrong, but the outlet is 120v, correct? So wouldn't it be I = 150/120, or 1.25A?

  • Like 2
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sahls01gmc Senior Enthusiast

sahls01gmc

Posted
Posted

Okay. Here's the equation:

 

P=VI (Power (watts) = Voltage (volts) x Current (amps))

 

With the numbers provided above, the available current (I, in amps)

should be...

 

I = 150/12 = 12.5 A

 

Yes, I am a physics nerd.

This is 120v AC, not 12v DC....

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CounterMeasure Enthusiast

CounterMeasure

Posted
Posted

This is 120v AC, not 12v DC....

 

You are correct sir! :)

 

And on top of it from my experience with the outlet, it looks likes its a modified sine wave inverter and not a pure sine wave inverter. This means that there are certain things like some chargers will not be too happy on that modified sine wave.

roadblock Enthusiast

roadblock

Posted
Posted (edited)

Does anybody know how many amps the 110V electrical outlets can handle? I'm wondering if I can run a Coleman air bed pump from one of these? Is it about the same as the 12V plug or more/less? I want to buy an air pump for camping, but I also want to be able to use it around the house, so 110V version is preferable it the truck can run it.

 

Thanks.

 

You will be fine, I have done this many times with no issue.

 

truck.jpg

Edited by roadblock
  • Like 2
  • Haha 1
ember1205 Senior Enthusiast

ember1205

Posted
Posted

Okay. Here's the equation:

 

P=VI (Power (watts) = Voltage (volts) x Current (amps))

 

With the numbers provided above, the available current (I, in amps)

should be...

 

I = 150/12 = 12.5 A

 

Yes, I am a physics nerd.

 

 

Nerd, maybe but correct, no.

 

Your formula is correct, but you solved for the 12V amperage and not the 110V amperage. Since the pump in question is a 110V device, it's THAT amperage that will dictate whether or not its current draw is too much.

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